Write an equation of a parabola opens upwards and has vertex (7, - 6).
Any help?
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Answer:
f(x) = x² - 14x + 43
Step-by-step explanation:
The equation of a parabola in vertex form is
f(x) = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (7, - 6 ) , then
f(x) = a(x - 7)² - 6
Since the parabola opens upwards then a > 0
let a = 1
f(x) = (x - 7)² - 6 ←in vertex form
f(x) = x² - 14x + 49 - 6
f(x) = x² - 14x + 43 ← in standard form