Find the equation of the straight line passing through the point (0, -1) which is perpendicular to the line y=-3/4 x-3
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Answer:
y = [tex]\frac{4}{3}[/tex] x - 1
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - [tex]\frac{3}{4}[/tex] x - 3 ← is in slope- intercept form
with slope m = - [tex]\frac{3}{4}[/tex]
Give the slope of a line m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{3}{4} }[/tex] = [tex]\frac{4}{3}[/tex]
The line crosses the y- axis at (0, - 1 ) ⇒ c = - 1
y = [tex]\frac{4}{3}[/tex] x - 1 ← equation of perpendicular line