If someone can help me with this question i’ll thank them forever!!
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Answer:
[tex]-\frac{3}{2}[/tex] < x or x > 4
Step-by-step explanation:
Convert the inequality to an equation.
2x² - 5x = 12
2x² - 5x - 12 = 0
Factor by grouping.
(2x + 3)(x - 4) = 0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
2x + 3 = 0
x - 4 = 0
Solve for x.
x = -3/2
x = 4
Use each root to create test intervals.
The solution consists of all of the true intervals.
[tex]-\frac{3}{2}[/tex] < x or x > 4
good luck, i hope this helps :)