Concrete has a specific heat capacity of 3.3 J/(g *oC). How much energy is necessary to heat up 2,000 g of concrete from 25oC to 55oC?
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Answer:
[tex]\boxed {\boxed {\sf 198,000 \ Joules}}[/tex]
Explanation:
We want to find energy and we are given the specific heat capacity, mass, and change in temperature. We must use this formula:
[tex]q=mc \Delta T[/tex]
where m is mass, c is the heat capacity, and ΔT is the change in temperature.
We know the mass is 2,000 grams, the heat capacity is 3.3 J/g °C.
To find the change in temperature, subtract the final temperature and initial temperature.
Substitute the known values into the formula.
[tex]q= (2000 \ g)( 3.3 \ J /g \textdegree C) (30 \textdegree C)[/tex]
Multiply the first two numbers and note the grams will cancel out.
[tex]q= (6600 \ J/ \textdegree C)( 30 \textdegree C)[/tex]
Multiply again. This time, the degrees Celsius will cancel.
[tex]q= 198000 \ J[/tex]
198,000 Joules of energy are required.