Find the area of the triangle given:
B = 3b^2
H = 12p^7b^19
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Step-by-step explanation:
[tex] \frac{3 {b}^{2} \times 12 {p}^{7} {b}^{19} }{2} = \frac{3 {b}^{21} \times 12 {p}^{7} }{2} = \\ = 3 {b}^{21} \times 6{p}^{7} = \\ = 18 {b}^{21} \times {p}^{7} [/tex]