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A 200-n sled of slides down a frictionless hillside that rises at 37â° above the horizontal. what is the magnitude of the force that the surface of the hill exerts on the sled?

Respuesta :

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. 120N is the component of GRAVITY parallel to the surface of the hill; the force exerted by the hill itself is perpendicular to the surface and is 160N. 

Answer:

159.72 N

Explanation:

The magnitude of the force that the surface of the hill exerts on the sled is equal to the normal reaction.

N = m g cos θ

Given:

m g = 200 N

θ = 37°

N = (200 N) (cos 37°) = 159.72 N

Thus, the surface of the hill exerts 159.72 N force on the sled.