write the first 4 terms of the sequence defined by its given rule 5. f(1) = 7, f(n) = -4.f(n - 1) + 15

Answer:
The first 4 terms of the sequence are: 3, 9, 81, 6561
Step-by-step explanation:
We are given the following recursive function:
[tex]f(n) = [f(n-1)]^{2}[/tex]
And the following initial condition:
[tex]f(1) = 3[/tex]
The second term of the sequence is:
[tex]f(2) = [f(2-1)]^{2} = f(1)^2 = 3^2 = 9[/tex]
The third term of the sequence is:
[tex]f(3) = [f(3-1)]^{2} = f(2)^2 = 9^2 = 81[/tex]
The fourth term of the sequence is:
[tex]f(4) = [f(4-1)]^{2} = f(3)^2 = 81^2 = 6561[/tex]
The first 4 terms of the sequence are: 3, 9, 81, 6561