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Would this be X method factoring and how would I do it if X isn’t alone to begin with

Would this be X method factoring and how would I do it if X isnt alone to begin with class=

Respuesta :

Answer:

Option C

Step-by-step explanation:

Given polynomial is,

x² - 3x - 18 = x² - 6x + 3x - 18

                 = x(x - 6) + 3(x - 6)

                 = (x + 3)(x - 6)

We can rewrite the polynomial in factored form as,

x² - 3x - 18 = (x - 6)(x + 3)

Therefore, (x - 6) will be one of the factors of the given polynomial.

Option (C) is the answer.

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