for what value of “x” is the figure the given special parallelogram?
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Answer:
x = 6
Step-by-step explanation:
(In reference to my diagram.... my diagram is similar to the diagram in the question)
We know that diagonals of a square bisect each other at right angles.
In ΔBOC ,
•OB = OC (Diagonals of square bisect each other)
=> ∠OBC = ∠OCB = (7x + 3)° (∵ OB = OC)
• ∠BOC = 90° (Diagonals intersect at right angles)
Using angle sum property of triangle ,
∠OBC + ∠OCB + ∠BOC = 90°
[tex] = > 7x + 3 + 7x + 3 + 90 = 180[/tex]
[tex] = > 14x + 6 = 180 - 90 = 90[/tex]
[tex] = > 14x = 90 - 6 = 84[/tex]
[tex] = > x = \frac{84}{14} = 6[/tex]