Answer:
NO. Ada is not correct.
Step-by-step explanation:
Using Pythagorean Theorem, find the length of the diagonal of the rectangle and the square, respectively.
✔️Diagonal of the Rectangle:
[tex] a^2 + b^2 = c^2 [/tex]
Where,
a = 8 in.
b = 16 in.
c = hypotenuse (longest side of a right ∆)
Plug in the values into the equation
[tex] 8^2 + 16^2 = c^2 [/tex]
[tex] 64 + 256 = c^2 [/tex]
[tex] 320 = c^2 [/tex]
Take the square root of both sides
[tex] \sqrt{320} = \sqrt{c^2} [/tex]
[tex] 17.9 = c^2 [/tex] (nearest tenth)
Length of diagonal SQ = 17.9 in
✔️Diagonal of the Rectangle:
[tex] a^2 + b^2 = c^2 [/tex]
Where,
a = 8 in.
b = 8 in.
c = hypotenuse (longest side of a right ∆)
Plug in the values into the equation
[tex] 8^2 + 8^2 = c^2 [/tex]
[tex] 64 + 64 = c^2 [/tex]
[tex] 128 = c^2 [/tex]
Take the square root of both sides
[tex] \sqrt{128} = \sqrt{c^2} [/tex]
[tex] 11.3 = c^2 [/tex] (nearest tenth)
Length of diagonal OM = 11.3 in.
SQ is not two times the length of OM.
Therefore, Ada is not correct.