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What force is required to accelerate a 1840 kg car from 4.77 m/s to 23.5 m/s,
in a time of 5.18 s? Hint: Find the acceleration first.

Respuesta :

18308287
A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
a = v - u by t
a = 23.5 - 4.77
a = 28.27 m/s^2

.:. The acceleration is 28.27 m/s^2

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