Write an equation in slop _intercept form of the line that bisects the angle formed by BA and BC
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Answer:
y = -x + 2
Step-by-step explanation:
Angle between these lines = 90°
Angle between BC and the angle bisector BD = 45°
Since, m(∠DBE) = 90° + 45° = 135°
Therefore, slope of the angle bisector BD = tan(90° + 45°)
= -tan(45)°
= -1
Let the equation of the angle bisector which passes through (x', y') and slope = m,
y - y' = m(x - x')
Where m = slope of the line = (-1)
Since, the angle bisector passes through a point B(-1, 3),
Equation of BD will be,
y - 3 = (-1)(x + 1)
y - 3 = -x - 1
y = -x - 1 + 3
y = -x + 2