Write the equation of the link that passes through point A and the origin
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Answer: Choice B
y + 3 = (1/2)(x + 6)
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Explanation:
Point A is located at (x1,y1) = (-6,-3)
The origin is located at (x2,y2) = (0,0)
Find the slope of the line through those two points
m = (y2-y1)/(x2-x1)
m = ( 0 - (-3) )/( 0 - (-6) )
m = ( 0 + 3 )/( 0 + 6 )
m = 3/6
m = 1/2
Now turn to point slope form
y - y1 = m(x - x1)
y - (-3) = (1/2)(x - (-6))
y + 3 = (1/2)(x + 6)
Note: We could easily swap (x1,y1) and (x2,y2) to get an equivalent equation.