You hang an object with a mass of 0.5kg on a spring, and the spring stretches 0.1m. If the stiffness of the spring is 50 N/m, what is the elastic energy stored in the spring?

Respuesta :

Answer:

0.25 N-m

Explanation:

PE=0.5kx^2; PE=potential engery, k=stiffness of spring, x=displacement

=0.5(50)(0.1^2)

=0.25 N-m