What is the product of 3y
product of (3y^)(274)
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3y^-4 × (2y^-4) = 6y^-8
= 6/1/y^8
= 6/y^8
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1) When x^1 multiply with x^2, 1 will add to 2 and become 3
= x^3
2) y^-1 = 1/y
3^-2 = 1/3^2 = 1/9
5^-2 = 1/5^2 = 1/25