Answer:
b. 120°
Step-by-step explanation:
K is any point outside of the circle with center M.
KJ and KL are tangents to the circle at points J and L respectively drawn from point K.
MJ and ML are radii of the circle with center M.
Since, tangent is perpendicular to the radius of the circle.
[tex] \therefore m\angle MJK = m\angle MLK = 90\degree \\[/tex]
Since, measure of central angle of a circle is equal to the measure of its corresponding minor arc.
[tex] \therefore m\angle JML = m\widehat {(JL)} \\
\therefore m\angle JML = 60\degree \\[/tex]
Since, JKLM is a quadrilateral. Hence by angle sum postulate of interior angles of quadrilateral JKLM, we have:
[tex] m\angle JML + m\angle MJK + m\angle MLK \\+ m\angle JKL= 360\degree \\
\therefore 60\degree +90\degree +90\degree +m\angle JKL= 360\degree \\
\therefore 240\degree +m\angle JKL= 360\degree \\
\therefore m\angle JKL= 360\degree-240\degree \\
\huge \purple {\boxed {\therefore m\angle JKL= 120\degree}} \\[/tex]
