The given regular polygon is an equilateral triangle.
The measure of one interior angle of it is 60°.
The measure of one exterior angle is 120°.
What are the measures of interior and exterior angle of a regular polygon?
For an n-sided polygon,
The sum of all interior angles = (n - 2)180°.
The sum of all exterior angles = 360°.
We know, that a regular polygon has all sides equal, all interior angles equal, and also all exterior angles equal.
Therefore,
The value of each interior angle of a regular polygon = (The sum of all interior angles)/n,
or, The value of each interior angle of a regular polygon = {(n - 2)180°}/n.
The value of each exterior angle of a regular polygon = (The sum of all exterior angles)/n,
or, The value of each exterior angle of a regular polygon = 360°/n.
How to solve the question?
In the question, we are asked to find the measure of one interior and one exterior angle of the given regular polygon.
The given regular polygon is a three-sided regular polygon, that is, it is an equilateral triangle.
∴ We can say that n = 3.
∴ The value of each interior angle of a regular polygon = {(n - 2)180°}/n.
or, The value of each interior angle of a regular polygon = {(3 - 2)180°}/3 = 180°/3 = 60°.
∴ The value of each exterior angle of a regular polygon = 360°/n.
or, The value of each exterior angle of a regular polygon = 360°/3 = 120°.
∴ The given regular polygon is an equilateral triangle.
The measure of one interior angle of it is 60°.
The measure of one exterior angle is 120°.
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