Answer: The change in internal energy of the gas is +408 J
Explanation:
According to first law of thermodynamics:
[tex]\Delta E=q+w[/tex]
[tex]\Delta E[/tex] =Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done on the system= [tex]-P\Delta V[/tex]
As volume is constant , [tex]\Delta V[/tex] = 0 and w = 0.
q = +408J {Heat absorbed by the system is positive}
[tex]\Delta E=+408J+(0J)=+408J[/tex]
Thus the change in internal energy of the gas is +408 J
