Answer:
[tex]a=-6\quad and \quad b=8[/tex]
Step-by-step explanation:
[tex]\frac{8-\sqrt{18}}{\sqrt{2}}=\frac{\sqrt{2}}{\sqrt{2}}\times \frac{8-\sqrt{18}}{\sqrt{2}}\\\\=8\sqrt{2}-\sqrt{2}\cdot \sqrt{18}\\\\=8\sqrt{2}-\sqrt{36}\\\\=-6+8\sqrt2[/tex]
By comparing the last expression with [tex]a+b\sqrt{2}[/tex], we get:
[tex]a=-6\quad and \quad b=8[/tex]
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