Given ΔADC and ΔAEB, What is AE?
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Answer:
As shown in picture,
EB is perpendicular with AC
DC is perpendicular with AC
=> EB // DC
Applying Thales theorem:
BC/AC = ED/AD
=> AD = ED x AC/BC = 72 x 88/55 = 115.2
=> AE = AD - ED = 115.2 - 72 = 43.2
Hope this helps!
:)