Answer:
[tex]|WX|=|XY|=\sqrt{18} =3\sqrt{2}\:Units \:or\: 4.2 \:Units\\|WZ|=|YZ|=\sqrt{34} \:Units \:or\: 5.8 \:Units[/tex]
Step-by-step explanation:
Theorem: The diagonals of a kite are perpendicular.
Let O be the point of intersection of the diagonals,
Applying Pythagoras Theorem, in right triangle WOX
[tex]|WX|^2=|WO|^2+|OX|^2\\|WX|^2=3^2+3^2=18\\|WX|=\sqrt{18} =3\sqrt{2}\:Units \:or\: 4.2 \:Units[/tex]
Applying Pythagoras Theorem, in right triangle WOZ
[tex]|WZ|^2=|WO|^2+|OZ|^2\\|WX|^2=3^2+5^2=34\\|WZ|=\sqrt{34} \:Units \:or\: 5.8 \:Units[/tex]
