If given the two sides of a triangle, the third side, x, must be greater than the difference between the given two sides.
The third side, x must also be less than the sum of the given two sides.
Given 5, and 10.
The third side, x > (10 - 5) x > 5
The third side, x < (10 + 5) x < 15
x > 5 and x < 15
5 < x < 15
The third side x, is between 5 and 15. It could be any 6, 7, 8, 9, 10, 11,...., 14
But since the question stated that the triangle is acute, x can be like 11.
You can use Cosine Rule to check the angles of triangle, 5, 10, 11. You would discover all the angles are acute.
Answer is option D.