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A radioactive substance decays according to the following function, where yo is the initial amount present, and y is the amount present at time t (in days).

y= y_o e^0.072t.

Find the half-life of this substance. Do not round any intermediate computations, and round your answer to the nearest tenth. days

Respuesta :

Answer:

[tex]t_{1/2} \approx 9.6\,days[/tex]

Step-by-step explanation:

The time constant of the radioactive constant is:

[tex]\tau = \frac{1}{0.072}\,days[/tex]

[tex]\tau = 13.889\,days[/tex]

The half-life of the substance is:

[tex]t_{1/2} = \tau \cdot \ln 2[/tex]

[tex]t_{1/2} = (13.889\,days)\cdot \ln 2[/tex]

[tex]t_{1/2} \approx 9.6\,days[/tex]