Evaluate g(n- 7) if g(x) = x^2-6/7x
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Answer:
A
Step-by-step explanation:
To evaluate g(n - 7) substitute x = n - 7 into g(x), that is
g(n - 7)
= [tex]\frac{(n-7)^2-6}{7(n-7)}[/tex] ← expand factor on numerator using FOIL
= [tex]\frac{n^2-14n+49-6}{7n-49}[/tex]
= [tex]\frac{n^2-14n+43}{7n-49}[/tex]
g(n-7) is evaluated to be [tex]g(n-7)= \frac{n^2 - 14n + 43}{7n - 49}[/tex].
We can find the value of a function when the value of the variable is given by, substituting the value of the variable throughout the entire function and then simplifying it.
It is given that:
[tex]g(x) = \frac{x^2-6}{7x}[/tex]
We have to find the value of g(n-7).
We can substitute n-7 in the place of x in the equation of the function.
This can be done as shown below:
[tex]g(n-7)= \frac{(n-7)^2 - 6}{7(n-7)} \\g(n-7)= \frac{n^2 - 14n + 49 - 6}{7n - 49} \\g(n-7)= \frac{n^2 - 14n + 43}{7n - 49}[/tex]
Therefore, the value of g(n-7) is evaluated to be [tex]g(n-7)= \frac{n^2 - 14n + 43}{7n - 49}[/tex]. The correct answer is option A.
Learn more about evaluating functions here: https://brainly.com/question/2284360
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