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circle E, and are diameters. Angle BCA measures 53°.

Circle E is shown. Line segments A C and B D are diameters. Lines are drawn to connect points B and C and points A and D. Angle B C A is 53 degrees.

What is the measure of arc AD?

53°
74°
106°
180°

Respuesta :

calculista

Answer:

74°

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

Triangle EBC is an isosceles triangle (because has two equal sides EB=EC)

so

[tex]m\angle BCA=m\angle BCE=m\angle EBC=53^o[/tex]

Find the measure of angle BEC

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

[tex]m\angle BCE+m\angle EBC+m\angle BEC=180^o[/tex]

substitute the given values

[tex]53^o+53^o+m\angle BEC=180^o[/tex]

[tex]m\angle BEC=180^o-106^o=74^o[/tex]

Find the measure of angle AED

we know that

[tex]m\angle AED=m\angle BEC[/tex] ----> by vertical angles

so

[tex]m\angle AED=74^o[/tex]

Find the measure of arc AD

we know that

[tex]m\ arc\ AD=m\angle AED[/tex] -----> by central angle

therefore

[tex]m\ arc\ AD=74^o[/tex]

Ver imagen calculista
bdizzle555

Answer:

The answer is B on Edge 2020`

Step-by-step explanation:

I did the exam

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