It says to solve for x but I don’t know how to do it
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Answer:
0 & 3
Step-by-step explanation:
(1/7)x² - (3/7)(x) = 0
Take (1/7)x common
(x/7)(x - 3) = 0
(x/7) = 0 when x = 0
x - 3 = 0 when x = 3
Answer: x = {0, 3}
Step-by-step explanation:
First, clear the denominator.
Then move everything to one side so zero is on the other side (because it is a quadratic equation).
Next, factor the quadratic equation.
Finally, solve each factor.
[tex]\dfrac{1}{7}x^2=\dfrac{3}{7}x\\\\\\7\bigg(\dfrac{1}{7}x^2\bigg)=7\bigg(\dfrac{3}{7}x\bigg)\\\\\\x^2=3x\\\\\\x^2-3x=0\\\\\\x(x-3)=0\\\\\\x=0\qquad x-3=0\\\\\\.\qquad \qquad x=3\\\\\\\large\boxed{x=\{0,3\}}\\[/tex]