Solve sin theta + 1 = cos2 theta on the interval

Answer:
Θ = 0, [tex]\frac{7\pi }{6}[/tex], [tex]\frac{11\pi }6}[/tex]
Step-by-step explanation:
sin(theta) + 1 = cos^2(theta) - sin^2(theta)
sin(theta) + 1 = (1 - sin^2(theta)) -sin^2(theta)
sin(theta) = -2sin^2(theta)
2sin^2(theta) + sin(theta) = 0
sin(theta)[2sin(theta) + 1] = 0
sin(theta) = 0 and 2sin(theta) + 1 = 0
sin(theta) = 0 and sin(theta) = -1/2
Θ = 0, [tex]\frac{7\pi }{6}[/tex], [tex]\frac{11\pi }6}[/tex]