Respuesta :
Triangle ABC is similar to triangle CEF.
Explanation:
Diagram is inserted for the reference.
ABCD is a rectangle.
ABC is a right angled triangle because all the angles of the rectangle are 90◦ - (a)
CEF is a right angled triangle because FE is perpendicular to DC – (b)
In triangles ABC and CEF,
1. Angle ABC = Angle CEF = 90◦ (Both are right angles from a and b)
2. Angle BCA = Angle EFC (Alternate angles on parallel lines are equal on intersection)
Hence using Similarity property of AA (Angle, Angle), Triangle ABC and CEF are similar.
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ΔABC and ΔCEF are similar triangles by the AA similarity theorem.
What is the AA Similarity Theorem?
The angle-angle similarity theorem (AA) states that when two triangles have two pairs of corresponding congruent angles, both triangles are similar triangles.
In ΔABC and ΔCEF, we have the following:
Two pairs of corresponding congruent angles - ∠FEC ≅ ∠ABC (right angles) and ∠FCE ≅ ∠BAC
Therefore, ΔABC and ΔCEF are similar triangles by the AA similarity theorem.
Learn more about the AA similarity theorem on:
https://brainly.com/question/2166570