Answer:
[tex]v=16.234m/s[/tex]
Explanation:
Given data
Distance S=6.10 m
Initial Speed u=12.0 m/s
To find
Final Speed v
Solution
From third equation of motion we know that:
[tex]v^{2}-u^{2}=2aS[/tex]
where
v is final velocity
u is initial velocity
a is acceleration
S is distance
Substitute the given values to find v
[tex]v^{2}=u^{2}+2aS\\v^{2}=(12.0m/s)^{2} +2(9.8m/s^{2} )(6.10m)\\v^{2}=263.56\\ v=\sqrt{263.56}\\ v=16.234m/s[/tex]
