Answer:
after 3.92 seconds
Step-by-step explanation:
Fill in the given value of h to find the formula for the height of the ball. Then set the value of that height to zero and solve for t.
[tex]h_2(t)=-16t^2+246\\\\0=-16t^2+246\\\\0 = t^2-15.375 \quad\text{divide by -16}\\\\\sqrt{15.375}=t \quad\text{add 15.375, take the square root}\\\\t\approx 3.92[/tex]
Ball 2 reaches the ground after 3.92 seconds.
