Answer:
The change in entropy of surrounding = -33.5 J/k
Explanation:
Heat gained by the ice = 10 kJ = 10000 J
Heat lost by surrounding = -(Heat gained by ice)
Hence,
Heat lost by surrounding = -(10000 J)
The given room temperature = [tex]25^{o}C[/tex] = 273 + 25 = 298 K
[tex]Change\,\,in\,\,entropy\,\,surrounding =\frac{Heat\,\,lost\,\,by\,\,surrounding}{Room\,\,temperature}[/tex][tex]= \frac{-10000}{298}= 33.5\,J/k[/tex]
Therefore, The change in entropy of surrounding = -33.5 J/k
