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A bicycle wheel of radius 0.70 m is rolling without slipping on a horizontal surface with an angular speed of 2.0 rev/s when the cyclist begins to uniformly apply the brakes. The bicycle stops in 5.0 s. Through how many revolutions did the wheel rotate during the 5.0 seconds of braking?

Respuesta :

Manetho

Answer:

θ= 5 radian

Explanation:

Given data:

Radius r = 0.70 m

Initial angular speed ω_i = 2rev/s

Time t = 5 s

Final angular speed ω_f =0

so we have angular displacement

[tex]\theta= \frac{\omega_f-\omega_i}{2}\times t[/tex]

putting values

[tex]\theta= \frac{0-2}{2}\times5[/tex] = 5 rad

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