There are six times as many whitetail deer as mule deer in the woods. If Jacob gets one deer in the woods? What is the probability that Jacob gets a mule deer?
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Answer:
C) The probability that Jacob gets a mule deer is 1/7.
Step-by-step explanation:
Let us assume the number of mule deer in the woods = m
So, the number of whitetail deer = 6 x ( Number of mule deer) = 6 (m) = 6 m
Also, the total number of deer = Mule deer + whitetail deer
= m + 6 m = 7 m
Let E: Event of Picking a mule deer in the woods.
[tex]\textrm{P(E)} = \frac{\textrm{Number of favorable observations}}{\textrm{ Total number of observations }}[/tex]
So, here [tex]\textrm{P(Picking a mule deer )} = \frac{\textrm{Number of Mule deers in the woods}}{\textrm{ Total number of deer }} = \frac{m}{7m} = \frac{1}{7}[/tex]
or, P(E) = 1/7
Hence, the probability that Jacob gets a mule deer is 1/7.
Answer:
C) The probability that Jacob gets a mule deer is 1/7.
Step-by-step explanation:
Let us assume the number of mule deer in the woods = m
So, the number of whitetail deer = 6 x ( Number of mule deer) = 6 (m) = 6 m
Also, the total number of deer = Mule deer + whitetail deer
= m + 6 m = 7 m
Let E: Event of Picking a mule deer in the woods.
So, here
or, P(E) = 1/7
Hence, the probability that Jacob gets a mule deer is 1/7.