Answer:
I = 11.26 mA
Explanation:
given,
V = 0.7 V length = 80 m
diameter = 0.2 mm = 0.02 cm
radius = 0.01 × 10⁻² m
[tex]resistance = \dfarc{\rho l}{A}[/tex]
ρ for gold wire = 2.44 × 10⁻⁸ ohm-m at 20 °C
A = cross sectional area = π r² = π (0.01 × 10⁻² )²
= 31.4× 10⁻⁹ m²
[tex]resistance = \dfarc{2.44\times 10^{-8} \times 80}{31.4\times 10^{-9}}[/tex]
R = 62.165 Ω
[tex]I = \dfrac{V}{R}[/tex]
[tex]I = \dfrac{0.7}{62.165}[/tex]
I = 11.26 mA
