The terms that explains the value of [tex]sin(\frac{\pi}{3} )[/tex] on the unit circle would be [tex]sin(\frac{\pi}{3} )=opposite[/tex]
"It is a triangle whose one of the angle measures 90° "
"The longest side of the right triangle."
"It is a circle with radius 1."
For given question,
We have been given a unit circle.
We need to find the [tex]sin(\frac{\pi}{3} )[/tex]
We know, in a right triangle for any angle [tex]\theta[/tex],
[tex]sin(\theta)=\frac{opposite~ side~ of~ angle~ \theta}{hypotenuse}[/tex]
So, for [tex]sin(\frac{\pi}{3} )[/tex],
[tex]\Rightarrow sin(\frac{\pi}{3} )=\frac{opposite~side}{hypotenuse}\\\\\Rightarrow sin(\frac{\pi}{3} )=\frac{opposite ~side}{1}\\\\\Rightarrow sin(\frac{\pi}{3} )=opposite[/tex]
Therefore, the terms that explains the value of [tex]sin(\frac{\pi}{3} )[/tex] on the unit circle would be [tex]sin(\frac{\pi}{3} )=opposite[/tex]
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