Answer:
The third option:
The object's acceleration is 0 m/[tex]s^2[/tex] for the first 2 seconds because the velocity is not changing. Then, the object undergoes a positive constant acceleration because the slope is positive and constant.
Step-by-step explanation:
First. I should note that the y-axis of this graph shows the velocity.
To see the acceleration, we should look at the slope of the velocity.
From [0,2] there is a slope of 0, this means that the acceleration is 0
From [2,4] there is a slope of [tex]\frac{1}{2}[/tex], which means that the acceleration is [tex]\frac{1}{2}[/tex] m/[tex]s^2[/tex] . This is a positive constant acceleration.
