Which ordered pair (m, n) is a solution to the given system of linear equations? mc015-1.jp g (–4, –1) mc015-2.jp g (–1, –4) (11, –16)
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Answer:
(-1,-4)
Step-by-step explanation:
6m-5n=14 equation 1
2m+2n= -10 equation 2
using equation 2 we have
2m=-10-2n
m=-5-n equation 3
using equation 1 we have
6*(-5-n)-5n=14
-30-6n-5n=14
-11n=14+30
-11n=44
n=-44/11
n=-4
using equation 3
m=-5-n
m=-5-(-4)
m=-1
finally we have
(-1,-4)
The ordered pair (m, n) which is a solution to the given system of linear equations is:
(-1,-4)
We are given a system of linear equations as follows:
[tex]6m-5n=14-------(1)[/tex]
and
[tex]2m+2n=-10[/tex]
which could be reduced as follows:
[tex]m+n=-5--------(2)[/tex]
( Since, we divide both side by 2)
Now, on multiplying equation (2) by 5 and adding both the equations we get:
[tex]11m=-11\\\\m=\dfrac{-11}{11}\\\\m=-1[/tex]
On putting the value of m in equation (2) we get:
[tex]-1+n=-5\\\\n=-5+1\\\\n=-4[/tex]
Hence, the ordered pair which is a solution is given by:
(-1,-4)