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Hi, PLEASE HELP! In △ABC, m∠A=32°, m∠B=25°, and a=18. Find c to the nearest tenth.
A. 28.5
B. 26.1
C. 25.2
D. 27.6

Hi PLEASE HELP In ABC mA32 mB25 and a18 Find c to the nearest tenth A 285 B 261 C 252 D 276 class=

Respuesta :

mpanderla95
To solve this question, you would need to use either sin or cos law to do this.

Sin 32/18 = Sin 137/c

c = 18sin 137/sin 32.

This should be the value of c.

Answer:

the correct answer is option A

Step-by-step explanation:

given,

∠A=32° ,  ∠B=25°    ∠C= 180°-(32°+25°) = 123°

a=18,

using sine law

[tex]\frac{sin A}{a}=\frac{sin B}{b}=\frac{sin C}{c}[/tex]

using equation,

[tex]\frac{sin A}{a}=\frac{sin C}{c}\\[/tex]

sin 123° = 0.0294 c

c = 28.5

Hence, the correct answer is option A

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