in the diagram below, AB and BC are tangent to O. Which equation could be solved to find y, the measure of ADC

Answer:
A
Step-by-step explanation:
∠ABC is formed by 2 tangents to the circle and is measured as
∠ABC = [tex]\frac{1}{2}[/tex] (m arc ADC - m arc AC ), that is
[tex]\frac{1}{2}[/tex] (y - 119) = 61 → A
Answer:
A. [tex]\frac{1}{2}(y^{\circ}-119^{\circ})=61^{\circ}[/tex]
Step-by-step explanation:
We have been given a diagram. We are asked to choose the equation that can be used to solve for y.
We know that measure formed by two intersecting tangents outside a circle is half the difference of corresponding arcs.
[tex]m\angle ABC=\frac{1}{2}(\widehat{ADC}-\widehat{AC})[/tex]
[tex]61^{\circ}=\frac{1}{2}(y^{\circ}-119^{\circ})[/tex]
Switch sides:
[tex]\frac{1}{2}(y^{\circ}-119^{\circ})=61^{\circ}[/tex]
Therefore, option A is the correct choice.