What are the zeros of the function f(x)=x^2+x-6 divides by x^2-x-6?
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Answer:
It is B.
Step-by-step explanation:
x^2+x-6 / x^2-x-6 = 0
The numerator equates to zero:
x^2 + x - 6 = 0
(x + 3)(x - 2) = 0
the zeroes are {-3, 2).
The zeroes of the function f(x) = (x² + x - 6)/(x² - x - 6) are -3, 2.
Hence, option B. is the right choice.
A function (say f(x)) is defined over x, when an expression in x, gives only one value f(x) for all the x in its domain.
A zero of a function (say f(x)) is the value x, where f(x) = 0.
We are asked to find the zeroes of the function
f(x) = (x² + x - 6)/(x² - x - 6).
To find the zeroes, we put the value of f(x) = 0, in the above equation to get:
(x² + x - 6)/(x² - x - 6) = 0
or, (x² + 3x - 2x - 6)/(x² + 2x - 3x - 6) = 0
or, {x(x + 3) -2(x + 3)}/{x(x + 2) -3(x + 2)} = 0
or, {(x - 2)(x + 3)}/{(x - 3)(x + 2)} = 0
Zeroes are where the numerator = 0, as the denominator can not be 0.
∴ (x + 3)(x - 2) = 0
∴ Zeroes of the function x + 3 = 0 ⇒ x = -3, and x - 2 =0 ⇒ x = 2, that is
-3, 2. Hence, option B. is the right choice.
Learn more about the zeroes of a function at
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