Which equation is y=(x+3)^2 +(x+4)^2 rewritten in vertex form ?
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Answer:
option B
Step-by-step explanation:
Given in the question an equation y = (x+3)² + (x+4)²
Step 1
Expand this equation
y = (x+3)² + (x+4)²
y = (x²+9+6x) + (x²+16+8x)
y = 2x² + 14x + 25
Step 2
Find the minimum point of the parabola equation, y = 2x² + 14x + 25
y = ax² + bx +c
x = -b/2a
= -14/2(2)
= -14/4
= -7/2
Step 3
Find the vertex point by plugging value of x in the equation
y = 2(-7/2)² + 14(-7/2) + 25
= 49/2 - 49 + 25
= 1/2
vertex (h,k)
vertex (-7/2 , 1/2)
Step 4
vertex form
y = a(x - h)²+ k
y = 2(x + 7/2)² + 1/2