(HELP ASAP HIGH POINTS) Which double-angle or half-angle identity would you use to verify the following:
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Answer:
B
Step-by-step explanation:
Using the trigonometric identities
• cscx = [tex]\frac{1}{sinx}[/tex] and secx = [tex]\frac{1}{cosx}[/tex]
Consider the left side
cscx sec x = [tex]\frac{1}{sinx}[/tex] × [tex]\frac{1}{cosx}[/tex] = [tex]\frac{1}{sinxcosx}[/tex]
Consider the right side
2 csc2x = [tex]\frac{2}{sin2x}[/tex] = [tex]\frac{2}{2sinxcosx}[/tex] = [tex]\frac{1}{sinxcosx}[/tex]
left side = right side hence identity is verified