A red die is tossed and then a green die is tossed. What is the probability that the red die shows an even number or the green die shows an even number?
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Using it's concept, it is found that there is a [tex]\frac{3}{4}[/tex] probability that the red die shows an even number or the green die shows an even number.
A probability is given by the number of desired outcomes divided by the number of total outcomes.
A die has six sides, of which three are even and three are odd, hence:
The "or probability" is given by:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]
Hence:
[tex]P(A \cup B) = \frac{1}{2} + \frac{1}{2} - \frac{1}{4} = \frac{3}{4}[/tex]
More can be learned about probabilities at https://brainly.com/question/14398287
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