Respuesta :

kudzordzifrancis

Answer:

[tex]\frac{2y+3}{7y-1}[/tex]

Step-by-step explanation:

The given expression is

[tex]\frac{10y^2+15y}{35y^2-5y}[/tex]

Factor both the numerator and the denominator.

[tex]=\frac{5y(2y+3)}{5y(7y-1)}[/tex]

Cancel out the common factors.

[tex]=\frac{2y+3}{7y-1}[/tex]

imlittlestar

Answer:

The correct answer is,

(10y² + 15y)/(35y² - 5y) = (2y + 3 )/( 7y - 1)

Step-by-step explanation:

It is given an expression,

(10y² + 15y)/(35y² - 5y)

To simplify the given expression

Taking 5y as common from both numerator and denominator,

(10y² + 15y )/( 35y² - 5y) = 5y( 2y + 3)/5y( 7y - 1)

 = (2y + 3 )/( 7y - 1)

Therefore the simplified form of given expression is given by,

(10y² + 15y)/(35y² - 5y) = (2y + 3 )/( 7y - 1)

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