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Use the laws of logarithms and the values given below to evaluate the logarithmic expression.
log7=0.8451 log5=0.6990
log3=0.4771 log2=0.3010

log12

Use the laws of logarithms and the values given below to evaluate the logarithmic expression log708451 log506990 log304771 log203010 log12 class=

Respuesta :

TaeKwonDoIsDead

Answer:

B

Step-by-step explanation:

We can use the logarithm property shown below to evaluate this:

[tex]Log(x*y*z)=logx+logy+logz[/tex]

Now we can write Log 12 as Log (2*2*3).

Using the rule, we can write:

Log (2*2*3) = Log 2 + Log 2 + Log 3

We are given values of Log 2 and Log 3, plugging these we get:

Log (2*2*3) = Log 2 + Log 2 + Log 3

Log (2*2*3) = 0.3010 + 0.3010 + 0.4771 = 1.0791

Answer choice B is right.

Wolfyy

We can factor out 12 using 2 and 3.

log(12) = log(2^2 * 3)

Rewrite it using the product rule [ log(xy) = log(x) + log(y) ]

log(2^2 * 3) = 2 log(2) + log(3)

Simplify using the given values.

2(0.3010) + 0.4771

0.602 + 0.4771

1.0791

Therefore, the answer is b. ≈ 1.0791

Best of Luck!

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