Answer:
33.2 m
Explanation:
The motion of the ball is a uniformly accelerated motion, with constant acceleration g = 9.81 m/s^2 (acceleration due to gravity).
The total displacement of the ball is given by
[tex]S=\frac{1}{2}gt^2[/tex]
where
t = 2.6 s is the time the ball took to reach the ground
Substituting t and g into the formula, we find the heigth of the building
[tex]S=\frac{1}{2}(9.81 m/s^2)(2.6 s)^2=33.2 m[/tex]
