Answer:
2 imaginary solutions
Step-by-step explanation:
3x^2 +6x+4 = 0
We can us the discriminant to determine the roots
b^2 -4ac where a=3 b=6 and c=4
6^2 -4*3*4
36 - 48
-12
If b^2-4ac>0 then we have 2 real roots
If b^2 -4ac = 0 we have 1 real root
If b^2 -4ac <0 we have 2 complex roots
Since it is less than 0, we have 2 complex roots
