Help please with this one
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Answer: 10.20 yd
Step-by-step explanation:
h² + 5h - 155 = 0
a=1 b=5 c=-155
[tex]x = \frac{-b +/- \sqrt{b^{2}-4ac}}{2a}[/tex]
[tex]h = \frac{-5 +/- \sqrt{5^{2}-4(1)(-155)}}{2(1)}[/tex]
[tex]h = \frac{-5 +/- \sqrt{25+620}}{2}[/tex]
[tex]h = \frac{-5 +/- \sqrt{645}}{2}[/tex]
[tex]h = \frac{-5 +/- 25.40}{2}[/tex]
[tex]h = \frac{-5 +25.40}{2}[/tex] , [tex]h = \frac{-5 - 25.40}{2}[/tex]
[tex]h = \frac{20.40}{2}[/tex] , [tex]h = \frac{-30.40}{2}[/tex]
h = 10.20 h = -15.20 (height can't be negative)