contestada

A force of 1.5 × 102 N is exerted on a charge of 1.4 × 10–7 C that is traveling at an angle of 75° to a magnetic field.

If the charge is moving at 1.3 × 106 m/s, what is the magnetic field strength?

8.2 × 102 T
8.5 × 102 T
3.2 × 103 T
6.4 × 1010 T

Respuesta :

Cetacea

Option (B) is correct.The magnetic field strength=8.5 x 10² T

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

B=8.5 x 10² T

Delgado007

Answer: B

Explanation:

Otras preguntas