Respuesta :
Given Function:
C(x) = 5/(x-2)
and
d(x) = x + 3
The domain of (cd)(x) can be calculated as:
(cd)(x) = 5/(x-2) × x + 3 = 5(x + 3)/(x-2)
The denominator of the function (cd)(x) can not be equal to zero because it would make it undefined.
Therefore,
x - 2 = 0
and x = 2 will be excluded.
Hence,
The domain is set of all the real numbers and x ≠ 2
C(x) = 5/(x-2)
and
d(x) = x + 3
The domain of (cd)(x) can be calculated as:
(cd)(x) = 5/(x-2) × x + 3 = 5(x + 3)/(x-2)
The denominator of the function (cd)(x) can not be equal to zero because it would make it undefined.
Therefore,
x - 2 = 0
and x = 2 will be excluded.
Hence,
The domain is set of all the real numbers and x ≠ 2
Answer:
all real values of x except x = 2
Step-by-step explanation:
look at the picture down below
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